20h-h^2=X

Solution for 20h-h^2=X equation:

20h-h^2=h

We move all terms to the left:

20h-h^2-(h)=0

We add all the numbers together, and all the variables

-1h^2+19h=0

a = -1; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-1)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-1}=\frac{-38}{-2}
=+19
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-1}=\frac{0}{-2}
=0
$